I saw the following circuit design posted to Facebook.
Source: https://www.facebook.com/share/p/1HuYVvXHcf/
What is wrong with this design:
No isolation from mains, potentially electrocutes if you touch any part of exposed LED strip.
The circuit will only give around 220V/30000ohms=0.00766.. mA current that can light one normal LED but not any long LED strip like shown in picture.
Most of the power (over 90%) taken by the circuit will end to be power loss on the resistors (0.75W for each resistor) so they will run quite hot.
If you disconnect the LED strip from the circuit, the capacitor will be fried sooner or later.
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