rajasekharnbkrist
Junior Member level 2
1. The current in a 20 ohm resistor is given by I=2+4sin314t. The current is measured by a hot wire ammeter. What is the measured value?
Should be about 3.414 amps. Unless this is a trick question?
That's it.
2 + 2*0.707 = 2+1.414 = 3.414 A
OMG!
This was weird of me. It should be 2 + 4*0.707 = 2 + 2.828 = 4.828A.
I got affected by the fact that kripacharya changed his answer from 2.828A to 3.414A at the instance I quoted it.
...
Am I wrong?
Klaus
OMG!
This was weird of me. It should be 2 + 4*0.707 = 2 + 2.828 = 4.828A.
I got affected by the fact that kripacharya changed his answer from 2.828A to 3.414A at the instance I quoted it.
I agree, the equation gives current ... no voltage....no restor needed to calculate the current.KlaussT !!!!!
First and foremost - the equation given is for current I, not voltage. So resistance is irrelevant.
Second, the sinewave component requires rms calculation, but not the DC component.
You have been tricked !
How did you get 3.414 ,explain clearly
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how did you get 3.414 , can u please explain clearly
RMS+RMS = RMS is only true for signals of same waveform, same frequency and sane phase.RMS+RMS=RMS. Why all the extra squaring/square-rooting?
Could you please explain why you say so.Calculating power with excel is irrelevant.